Ouendo to appear to the Press that my booklet of
Since it is not possible for you, which of the Dialogues are delineating, to be given firm support by the son-in-law of ∫S2%, S. LA S, I have tried to give them to him, so that they don't fall, just erect them. He is
True, what will the A.C.S.S. say about what it hurts, and then about what it merits; sÏ because I
I'm sorry.
unworthy of your prayers; sÏ because I've been elected an honorary member of the board of directors for a long time.
Major de?egni.
2ta " as the most magnanimous magnanimous can pity me; cosÏ the fear
that bÚ hauuto de precipices
they, can you weaponize it. And why is A.& S. not worth the little effort
by me, aue
gnache, po'cia per l'inondazione opragionta, 6 a? idui business of my ∫rencipe.
not inability in the
2onte opra Arno in Pi; cosÏ you won't be able to drink a few of my wines, while for the
them with?er
the situation is necessary and sÏ has great support. I don't think of it as humble, like
of course
I pray for true happiness, and I bow to it deeply.

that
"What's wrong with the attitude of an inclined person?
Ready for the joy of others: ∫ s∫ and ∫ndomi ‡ que?to end up employed with particular diligence to impo?e??arms of the factual practice of ∫gno, what did I judge to be looking for my prophet of Architecture, and also to addu lare to my genius bowed? I believe that pi˘ have some bad habits in learning them: I'd badly use my vigilance in such an ercithium, to highlight the benefits of the glamorous events I've done there. t, Art: At which so much pi˘ gladly I am, how much have I elaborated everything with the count of the best criteria in this prophecy; and what I appreciate from the reading of those, that f˘ put every day with a lot of age in Pro? It's still the others who delight in the work of Untitled, and make it easier for her to take over sÏ and to praise her, so that I can believe, that she will not have my work in this
...in those difficulties, that others say that the acts before them...
to me , while in the reddu
∫gno Ë " I don't have the ability to do that. Well, it's true,
which, as in all the Arts and Sciences, have the principles of difficulty, 6 are not apparent, but real, cosÏ.
I'm sure there's a lack of consistency in the principle of lines between them, but not between them.
Confu?e, it makes me
A doubtful thing? The etiquette of the moment. "The diligent continuation of audio makes it easy for me
"The corpus is a gluttony to tell her, 6 praxis to her & ?" "to "tread on the trade and understand them, and take possession of them even to those to whom you want to shame them, and why in there I'll have to meet with
Some friends are here with the bosses, here with the dances...
continue to remind me, and then another extension to the lessons that I've been doing with you: so I'll take those long suits, which I don't have to deal with, and I'll take that part of my chest.
who to uncle uncle's tents.

There is a part of Proposition, called at least Practice of which I mean, not a part, but a part of the perpendicular surface of all those that are
∫8248. ∫8248 is the only way to keep an eye on the world. In which three necessary factors are involved; the eye's weight, the height, and the height,
All three of them are well and well on their way to the point, proceeding all the way from seeing, it's only necessary.
... which are clearly placed, denoting the first as the first, in which the three cone are admired, the other as much as many, and the third as much. And even though it would also fall into the same category.
A fourth entity, that is, the perpendicular upland, which is the cell, is another, in which to govern.
of the view; which perpendicular surface can be seen behind the view, pi˘.
∫ in the mede?imo, ouero pi˘ ver?o l'occhio; ma non cadendo a propo?ito no?tro pone ciÚ in con?i
we'll put the other three aside, we'll talk about the other three; which of them will be in the same place?
which is how to place it: thus forming two points parallel to each other, representing each other.
The other eye, the other one is the same, 8 ambitions two for the other eye, indicating the height. But it's two.
ways, that other people can use, to put what plan in the heart, the Fifth by way of intervention
the other because of the painting; therefore, I will give principle to the principle of both of them with the
We both enjoy each other, and the other, just like the way we both do it, but who only make wine.
forms. And why is it necessary to first seek the truth of the fact to secure the proposition, which of the two of them
the perfect way, that's what I'm talking about with this figure.
Both the plan of Tauola, is ABCD, on the other hand, and the EFGH square, & dextermina, how much of it we want to look at the square, let's say how much it is from E or O, & how much
To the other side, see the side of the square EF, & how much is from E is M. Draw the lines.
OI, & M I, at right angles to them; & where two lines will form the angle, he will find the eye, which is at point I. Pull the "FI line", and then you will cut the M N line, in the
Oily L, what a long time ago we saw the side of the so-called square EF, a little in the heart with the praises.
said of the table, how much it is from E and L, including the table in the line M N: which otherwise represents
It wouldn't be perfect.

The square ABCD, equal in size to that of the EFGH figure, is the same as the square on the EFGH, and S i∫ extend the line on the A B side of the square on both sides, (which is the same as the square on both sides).
∫S∫ will call the line of the plan) then take the line from the floor, how much?
the eye from the square, i.e. from E to O, and which is brought into the previous figure, cut the plane line from the angle B to the point E; remove the other line from the opradette as far as it is from E to M,
The square is similar to the line of the plane in the previous figure from the corner B‡ F. (Auerta, O that I place said square outside the line of the plane, to make the confusion with the other lines, & ciÚ
I'll keep in the other figures). Bring the two figures to the plane line, then raise two lines to points E F, at right angles to the plane line, by how much height you want, but equal, that at the
- v - - pre?ente we will figure how much and from F‡ H, & from E ‡ G: (that cosÏ said two points G,8 H, will come to us
called Fvno, that is H, of the competition, 8, the other G, of the competition)?
The side of the square AB, at the point of the competition H, then the side of the square B D,‡ cut off the line of the
Plan BN, & pulled the NG line, (which Diagonal will be called, & or you will be called the said line will cut the B H line, which is in P, which is the P Q line, which is the same as the plan line, which is the same as the plan, which is the same as the plan.
then your square in your heart by way of interactivity, as you can see from the QPA B angles.
Both of you pulled a line perpendicular to the line of the plane, which starts from the circle of the square B, and the square BM; and then the "Diagonal NG, inter alia, the so-called BM, at the point O, and then he? The other line IL, parallel to the line of the plane, which cosÏ will then again see the square in the heart because of the square, as seen in the corners of the AB.Et to certify, which of these? The two squares are slightly different, as shown below, and the fact that I tell the story between: "Let's look at the first figure from Pontus E to L, and meet with the two of the previous body RP.8: OL, which will be shown". Like OL, that is to say, that the square in the heart because of the perfect picture, not the other one, because the side of the square BD, as well as the difference from PR, would be less seen in the heart.
O L . 
But why putting in the heart because of the picture would be long, and more confusing than the other because of the many lines of pi˘, which need to contribute to it: the other way of erecting the other way, which is more canovniform. And then, with the line drawn, which starts from point N to point L, which is longer than the cut of the GH line, in point S, which is longer than the point of the line in point G. That cosÏ is to operate each time the two of them want to go through the interception, and everything is the same as the other way of the picture. Which is easy to do, because if you want to form any kind of proposition, you first have to find the point of the painting, with the middle squared petiole in the heart because of the painting, and then find the point of the painting again. The point of the scene, how is it found, then continuing the operation by way of interception, which in this way will escape the multiplicity, is the confusion of the lines, which many people meet: & the operation: it is the result of
...in perfect conformity with the divine. Assuming that I will continue to provide you with the necessary information throughout the world.
C TO P. I I I.
It's good that the figure could be unknown even if we put it in the right place in the middle of the race and squared off with the middle, but it would only change the point of the competition,
i‡9243
The eye is depicted as the eye, which in a place where it is placed on one side, as in the other, as in the two figures in the square. Which, for the sake of simplicity, I will put in practice in the figure. So let the squared plane of the ABCD, & the height of the eye E, be the height of the competition,
at which the lines A, E& BE, & then draw the line of the plane extending the side of the square A B, up to G, which is precisely, how much is the direction to aim and square, from which point G you inhale
vna line at right angles with the plane line, 8 of such height, forming a line with the point E pa
washer at the floor line, which is called "F", as the point of the diatribe: & similarly.
pull the Diagonal line BF, and you will find the AE line in I, where you pull the IL line, paralell
to the line of the piano, which cosÏ is a bit like the square in your heart, as seen from the corners...

c A P. I v.
If you want to place a square in your heart, which with the corners M∫: touch the plane line, it will form the square ABCD; the plane line E F, & the
∫s∫ point of competition H, & that of G: "I then do the L line, paralell to the
line of the plane, touching the corner of the C-square, & shooters at every corner of the square there.
at right angles to the line of the plane at the touch of a line, as seen by M NO, the line of the plane.
then pull the MH, NH, BH, & OH lines; then press the line from the IL line, to the anne.
D jet, & flow rate from floor line O P, & another one from line IL to the anne
A, & OQ flow rate: &the third from line I L, to the other corner B, & OF flow rate: pull diagonal lines FG, QG, & QG, & PG, & where they will intersect OH; he will form
in paralell with the line of the plan, as they see the scaffolding, which will cut you off.
lines tending to H, he will retrace the corners of the square a little bit in the middle, that is to say, in the middle B the an
golo pi˘ away from the line I L la la la, from the Diagonal which starts from the point
F, & where the paralell is dotted natively by the diagonal FG, between the line BH in S, where the angle B is retracted; & similarly the angle A, with the diagonal QG, in R, & the angle D, with the diagonal PG inT, & the angle Cin N; since " C, touches the line IL, which runs
to the line of the plane, which is then retracted at the same angle...
and square in the corner, as seen from the RSNT corners.
C A P. V.

And then he wants to put the Equilateral Triangle, the ABC Triangle, & the "S" line of the DE plane, the point of the competition H, & the point of the G plane, forms the FB line at
gS∫ right angles with the plane line. Make the lines A H, FH, & CH, and then press the
From corner to corner Ballast plane line, S flow rate to CE line, pull the Diagonal EG line,
Where it will cut the line CH, at the point L, where the line IL is formed, paralyses the line of the plane: then pull the lines IF, & FL, which is a little bit in the triangle, as you can see from
corners I L F. Et to find the point of your mezaria again, the first time you draw the line, which starts from the corner
A, & go to the mezaria on the B C side, & where it is called the B F line, in N, where it is located.
the mezaria of the Triangle plant. Which then precieve the BN, & flow rate of the line of the
plane CM, and after having drawn the Diagonal MG, it will be called the CH line, the line of the plane, as it sees formed of points; and in the whole, which it will do with the CH line, the line of the plane, as it sees formed of points.
to the FH line, in O, where the Mézaria d'eau is located.

C A P. V I.
In the same way, place in the heart a triangle touching the line of the plane with the "Vi angles; it forms the triangle, which is the ABC, the line of the DE plane, the point of the competition, G.8.
ass∫, the one of the F area, pull the AM.8 CL lines at right angles with the plane line.
then pull the line HI, parallel to the plane line, which touches the angle C: then pull the lines MG, LG, & BG, & pre the line from line H I, to the angle A, & flow rate from the line H I, to the angle A, & flow rate from the line C to the angle C: then pull the lines MG, LG, & BG, & pre the line H I, to the angle A, & flow rate from the line H I, to the angle A, & flow rate from the line H I, to the angle A, & flow rate from the line C.
planBN, & Likewise the other one is in the corner B, also brought to the pin line no BE; then the diagonal lines NF & EF; then the diagonal lines NF & EF; then the line B G, they pull paralell lines in the line of the plane, as they see them formed of points, which are said to be in between.
The lines in G will be the angles of the triangle in the middle: that is to say, they will have the line
Diagonal EF, interacross the BG, in O, he will find the corner that runs to the other of the plant.
of Triangle B: The paralella, which is similarly paralyzed by the Diagonal NF, will also be the MG,
In P, the other corner, which runs around the other corner, is the corner of Plan A: & opts for the plane line.
at the L point, you will find the third of the line, which you run at the corner C: then you pull the L O lines,
Or P, & PL, a little bit and Triangle in the heart, as you see in the previous figure from the corners
POL.

C A P. v I 1.
the Pentagon plane ABCDE, the line of the Plan GH, the Ponto del Concor?o L, & the "Si della di?tanzaI" line at right angles with the line
∫ of the plan at the touch of a line: let's make them all compete, & reduce all the lines at the
point of competition L: when the FM line is made, it paralyzes the plane line, touching the angle E, take from said FM line, at the angle D,8 reach the plane line QN, and again the plane line QN.
from said line to corner C, & range QQ : by taking the two other corners A, & B, & Pa
Bring QP, & QH: then pull the Diagonals HI, PI, OI, & NI: & where the lines are said to be inter-lines.
They will ask the IQ., who will draw lines paralel to the plane line, as they see them formed by points: & douce? and lines of points between them will show the lines tending to L, each one for the place where they will meet again the corners of the Pentagon in the corner, i.e. the corner E, touching the FM line, will have the same angle.
place where the line of the plane at point R, angle D, point S, angle C, point T, angle A, point V; & " of B, point X; which then make the lines from angle to angle, there is the said Pentagon in the right hand, as seen in the previous figure for the VXTRS angles.

E? plicationone
Some figures, I think. habbino∫acilitato Ë ba'tanza la trada rrintendere
0 any way to put any plan into the heart, even because the multiplicity of plans can increase the difficulties in understanding, we will continue the discussion:
to put the plan in the right place. Let the so-called ABCDEF plan be the line
of Plan G
H; the Competition Pontus L, & the Competition Pontus I, pull the lines at right angles.
with the plane line VC, &T D, draw the lines from the points VA BT, at the point of the competition L, face the line M N, parallel to the plane line, touching the corners E F: then take the line from the line M.
and N, at the corner D, orero C, which are parallel to the M N line, and the flow rate is the line of the plane I O; and if you take away another one at the corner B, orero A, and you take away another one at the corner TH; if you take away the Diagonals OI, & HI, & you take away the TL line, you take away many lines of the TL line.
points, paralels to the line of the plane; & doue e? and inter? e will echo the lines tending to
In L, he's a hangout
They make the corners of the world, as they are, like the ones in your pictures. What cosÏ
♪ A little while ago ♪
the first floor, as you see for the ABSR QP corners.

Encche l'attione dell'i corciare il cerchio, ia maniglianti? ai duepa? ai duepa? ate trationi, B ∫ non douendo i altro di pi˘ operare, che di ritroarunque angles in e, compartendo, cioË a cirque
∫ conference in many parts, here and in many corners for those, alluia because in how many pi˘ parts of the circle, so pi˘ perfect is there a reduction; therefore I formed
Please note: pi˘ is easy for beginners to understand. So the circle
A, which of the twelve parts of the circle is to be used to draw the line of the plane BF, the point of the competition E, and the point "B," to send lines at right angles to the line of the plane in each part of the circle. Let them compete with many other lines at the point of the competition E, and let's see again the Diagonal FD: and where the lines tending to E are drawn with the line of the plane, "they are formed of points, which then erupted.
the same tile as in the previous figures; and when the circular line is drawn from one point to the other, it is a circle in the heart, as seen in the previous figure G.
True? I'm sure that you can also understand the previous trations, but I won't consider "the other of pi˘ as an effect: even if it's still going to erupt to find the parts of the circle...
∫ petiole, con la diui?ione del grande, cueto quello del grande, con la oladiui?iens del grande, con la oladiui?iens del
small, in the middle of time, form the two circles within the other, with the center A, the middle A, the middle A, the middle A, the middle A, the middle A, the middle A, the middle A, the middle A, the middle A, the middle A, the middle A, the middle A, the middle A, the middle A, the middle A, the middle A, the middle A, the middle A, the middle A, the middle A, the middle A, the middle A, the middle A, the middle A, the middle A, the middle A, the middle A, the middle A.
of which part of which one, or in how many parts, do you want to go to the previous twelve: to find reeds in the other one?
The parties, for each one of them to compete lines at the point of the center of the circle, must cut the circle petiole, or longer, they would cut the big one, he or she would cut the lines of the other circle. iritroverann∫ Again, the lines of the other circle. Send lines at right angles with the line of the plane,
that start from each one of the areas in which the circle touches the line, and then to the point of the
The contestant, the one from the competition and the one from the competition E, made all the lines to the point of the competition,
The Diagonal CE, or the intercommunicating Diagonal CE, is in line with the lines tending to D, forming the
I give for each one of them the many paralell lines with the line of the plane, as they are formed of points that
where the said and intertwined lines will echo with the said lines tending towards D, he who has found the parts of the two...
Circle each one for your place, how are the people in your country, cosÏ
You have two circles in your heart, as you see in the previous figure F.
To compete with the short, faithful wnaguide, even for non-literary trade, makes
I'm going to check the chimney.
You can easily find the one you know who's not on the street.
Thurs. The course at ∫ slowly with the point of the passage is not able to go the wrong way, but to do so at the point of the passage, which is the point of the evil one, 8. There is no doubt that while wool is not losing its Pole, although in the middle of the sea, whoever finds the shipwreck easily arrives at the port, but the sea is the sea in which the camp's operations take place. In the sea of the lagoon, it is necessary to confuse the lines, while they don't make the point of the sea, from which they have to make their way, so that the port of the lagoon doesn't disappear.
to your real place, which is very important in the future.
It was my fault, as it has happened many times between bringing the great unknown, or with other laborious innuendos, and, beyond the danger of wandering, so I have taken the opportunity to do the necessary work, ∫ but how could I do it? The above mentioned point of the document is to set out which plan in the heart, with the preexisting body. Form a plane, with the ABCD, the line of the EF plane, the line of the G plane, the point of the competition, the line of the G plane, the line of the G plane, the line of the EF plane, the line of the G plane, the line of the G plane, the line of the G plane, the line of the G plane, the line of the G plane, the line of the G plane, the line of the G plane, the line of the G plane, the line of the G plane, the line of the G plane, the line of the G plane, the line of the G plane, the line of the G plane, the line of the G plane, the line of the G plane, the line of the G plane, the line of the G plane, the line of the G plane, the line of the G plane, the line of the G plane, the line of the G plane, the line of the G plane, the line of the G plane, the line of the G plane, the line of the G plane
At the point of the competition, G: "I then drew a line, which I "jinqual"...
The line of the line of the pious no, and then to the previuos I, pulling a line from that point to the point of the imagined line, which is then pulled the MN line, paralyzing the plane touching the corner of square G: also take the line from the MN line, until the D or B angles, which are the same:
the line QG, & where it will cut the IL, in other words, the pull is paralell to the line of the plane as it sees formed of points, it is in the entirety of the many, 8 the flow rate opts for the line of the plane IO, & pull, which will do the same with the lynxes IG, & ZG, in SV, which will find two corners of the square
in the first line: & taking a new line from the MN line, at the corner A, & flow rate from the planeIP line; and pulled the PG line, 8 dous called interacer‡ la II in R, and then the PG line, 8 dous called interacer‡ la II in R, and then the PG line, 8 dous called interacer‡ la II in R, and pulled the PG line, 8 dous called interacer‡ la II in R, and pulled the PG line, 8 dous called interacer‡ la II in R, and pulled the PG line, 8 dous called interacer‡ la II in R, and pulled the PG line, 8 dous called interacer‡ la II in R, and pulled the PG line, 8 dous called interacer. The other paralell of the plane, 8 in the intercomparison that will be done with the AG inTivi is the other angle of the room. "Then, pull the lines from angle to angle; then, pull the lines from angle to angle; then, pull the square like ∫.
see for the anglesSTVA, punt∫ of the newspaper, but ∫lo imagined. Er to certify the perfect operation of tirat∫ the ZX line, which will happen at the point of the image of the Tanzania, and will be dictated by the dictation of the lines tending to G, as drawn by the figures, which will see that the interactions, with the lines drawn paralellar with the line of the
plane and

. , , , , , ! .


by using the same way as the sideliner-format plan.
It's like circulars, so that I think everyone from those places will come to be unaware of each other, that
iS∫ iS∫ I'll come to the front of the elevation, which is the only thing that will happen there.
The same level of many floors, much less level on the other, as pi˘ is less from the eye: "Why do you put any of the above in your chest"?

How many plants to make, how many were there? Plans, like other hann∫ in the world, what else can I do?
that some people don't have a good reason for it when it happens that some people don't have a good eye.
Because of their low level of training, it's impossible to make them perfect; but in order to make them better, I'll give them the chance to practise in a different way. 
Therefore, be warned, that the plants that will have to be placed in the heart, in order to put in front of whatever leaf is raised, will have no other choice but to grow it, which has been healed from the widths of the heart, since it is up to me to take the height, which is, moreover, true. What can they do and plants, by making them two points, and of the competition, 8 of the race, pi˘ is less high, even if they are raised, but also 8 perpendicularly: that all the streets surround my adventures.
you, as you'll find in the figure.
Let it be the square A BCD, the line of the plane EF, the point of the competition or the first height N,
And the one in the di'tanza. I'm sorry about the rules before and squared in the middle, which is a bit of a stretch.
B: then extended the lines NF, & ME, equally, it's the point of the competition in H, & the point of the competition in G: equally alkaline. Put the new points in H & G, the two points in H & G.
said square in the heart, which is A BIL; which is between clearly, so clearly, so much and so far from the first one.
Squared in the middle with the ba dots, as much as the other with the high dots: As the line was pulled
SR, at right angles, with the line of" and "a line touches" equally all the two angles of the sfion.
The two squares, which you can't see pi˘ of the other one, wouldn't be on the same line.
It was necessary for both of us to get to another operation before I could.

C A P. X I V.
The plan of the triangular body, in line with the previous ABC rules, with the "si punto del concor?o H, & il punto della di tanza, ouunque ?i vuole, perché al pre?ente non ca: is∫ ?ca in alcuna coneratione. Both "the line of the plan from vna part, which returns pi˘
as per the above mentioned paragraph, the competition's punt∫, and two lines with right angled lines pi˘ are as per the EG. Terms and conditions of the height of the triangle, 8th of which the GH line operates, by tant∫ of the G line, how high with the eye, 8th of which the Ga M line is 8th of which the G line is 8th of which the Ga M line is 8th.
EM, (what's this line I've called of the Plan's descent, which is a line for the pious, the body, which must be put in pro breast) and similarly on each floor, which must be put in the same way on each floor.
Find in the body, which one should be put in the line of the EF plane, since the first one is in the E point, and there is no vertical drop in the other. And why at the
Before the competition, two flat oils will have made two E & N oils, which will point to the height of the triangular body perpendicularly. Which one to find it again?
in the infrared mode, that is, the mezaria in the equilateral triangle plan, with the rules.
Tell me, what's the point P, then the line O PO, in the Triangle, 8 que'te mede'ime mi
The line from whichever side of the line you take, 8 which is the R.T.D., i.e. R, denoting the point - to O: S, the P: & T, the Q point. Lift up perpendicularly at point S.8 and then take the E.
on the side of the Triangle, which at the R point, cut the perpendicular at the V point, in which way the height of the triangle is retracted. What's that?
In another way, retrace it, & with taking it in the plane of the Triangle from point O, to point Q, & that carried by T, is to cut a "perpendicular line in V, which is the same as the medeim. When retracted to height SV, the flow rate, as it is done, is the line of the EN plane,After pulling the NM line, then pull lines paralell to the plane line, which start from every corner of the ba and Triangle up to the trajectory of the EM, & NM lines, as they see them.
a lot of stitches. And why are the two corners of the Triangle parallel to the line of the plane at the same time; 8 is the line, 8 is the point where the point L is both, 8 is the same as the other paralell line, which is part of theIntO,
D, & camina in the point I, denotes the height, it's a triangular body: that you then pull them there.
EI, &IL, I will retrace the degraded profile of the triangular body. Make a line to the line that operates as the person, where the body must be in the prostate, and the body to the XY department. "Go to a line perpendicular to the YZ: pull again on the line to
right angles opts for the line of the plane, where to find the point of the competition H,& FH. Whether before or after the "FH" line of Triangle C, and brought by the YZ line, cut the
XY line, in point 2. which denotes the angle C which is not suitable for the plane line. Take again the direction from the line FH to the angle B.8, which is the same flow rate as the angle FH.
YZ line, make it in 3.8 then remove the height from the GE line, at point L.8 brought by the YX line, cut the third line in which the angle B is retracted. Be still in front of the "FH line at the third corner A, and also within reach, from the YZ line in 1.
the height from the GE line, to the L point, & flow rate from the XY line, ‡ cut off the ‡gno 1 which denoter‡ the ter
Zo Angle A. You have to remove another one from the FH line at the point of the mezaria del
Triangle After in I Corcio, 8 carried by the YZ line in 4.8 seconds and still removed from the height of the
the GE line at point I, & carried by the XY line, ‡ cut off the 4. what denotes the height, 8 halves
riad and triangular body, which you then form the lynxes the 2.2:3.3:4.4:1.& 1:3.cosÏ ?arpo?to the goddess
triangular body in Pro? pettiua.

c A P. x v.
H, Taglian?i said two lines with right angles, with
and lines, 8 EG, 8 height, from which you can aim and body, GM. Place the height
body opts for the floor line, 8 EN.Tiran's EM, & NM lines, & do the perogn'an
The plant is filled with many lines paralell to the line of the plane, as they are formed of points," chimney after the cut of the line of the EM plane slope: doing then p∫ "it seems, it's nice, S? the TS. iritis a straight line, which is the same as the XZ, which is the one where the perpendicular line XV is raised: then you take the straight line from the ST line, at the corner of plant C, & the ports from line XV, and cut the line XV.
XZ at point 1 at which point the line is perpendicular to the height EN, & carried by the puncture.
to cut and perpendicular to point 7. You take the mira from the ST line, corner D,
Ports from line XV, at point 2 above the height from line E Gal point O, at point 2 above the height from line E Gal point O, at point 2 above the height from line XZ, at point 2 above the height from line E Gal point O, at point 2 above the height from line E Gal point O, at point 2 above the height from line XZ, at point 2 above the height from line E Gal point O, at point 2 above the height from line E Gal point O, at point 2 above the height from line XZ, at point 2 above the height from line E Gal point O, at point 2 above the height from line XZ, at point 2 above the height from line X
Cut off the point O, & R,8 brought from point 2.to cut the perpendicular at point 5. Let's also cut the perpendicular from the ST line to the B.8 angle from the XV line to point 3.
Cut from the EG line, at point P, & carried by the XZ line, ‡ cut the 3 at right angles, & remove the PC height, from the said point 3.
at point 6, That you draw the lines 1:2:3,7;. & 5:6, to the middle of the cube body in Pro
...and continuing the rule of the rule, put the rest, as you see for the 1:4.4:3 lines.
6:8. & 8: 7.
c A p. x v I.
IalaPiantade??o corpo , con le pa? ate "in I'corcio ABCDEF, il punto del con
- The line of the GL plane: the paralell line at the point of the competition.
∫ H, &la trauer?ante and two right angle lines IL, & the point of the height M.Siano fatte le
paralell lines are those of the plane, which touch every corner of the plant, as they see it.
formed of points: & perpendicular to the line of the GS plane, which one is the cruir deue
to get the E.M.T.'s,
Let's first retract the height of the body perpendicularly, 8 cm. with pulling a line in any place, operate my TV X, as they see it YZ AE: &...
raise it perpendicular to the Z point. Then, remove the mirae from the AD T, which is on the side d∫vno of the Triangles "Body, is brought from the Y point and cut the perpendicular Z.AB at the point. AB; &
Remove the other mira, which will erupt from TX, & bring it to point AE, cut the perpendicular Z.AB at point AB.
Z.AB, what are you looking for in that little spot? AB: What cosÏ is the height of the body perpendicularly retracted, 8 Z AB, the height of the flow rate is the line of the LN plane, and the lines are the same as the height of the body perpendicularly, 8 Z AB.
LM, & NM . Let it be pulled whatever it takes, whatever it takes, whatever it takes to govern it and whatever body it has in the chest. 
a line, as you can see with the numbers 1.8 2. & similarly, raised in point 2.
2.& 3. Then remove the E.8 from the GS line, at the corner E.8 brought by the 2:3 line. ‡ ta
line 1:2 in step 4. S: again, remove the miracle from the said GS line, at the corner F, & flow rate.
from the 2:3 line. to the height from line IL, to the height from line N, to the height from line 2:3.
nea 1:2, to cut off point 6. & to cut another me from the GS line, at the corner D; & por
from the line 2:3, to the height from the line I L, to the point O, to the height from the line I L, to the point O, to the height from the
line 1:2. ‡ cut off point 5. Be pre]nouveau de nouveau from line S Gall'Angle C, & flow from the
the 2:3 line. The line was 8 seconds and another one was taken from the line at the corner B, and carried by the 2:3 line in 7 seconds and also another one from the GIA line,
The height from the line 2:3 to the line R,8 is the same as the height from the line IL to the point R,8:
then cut the height from line 1:2. Cut the 8th line and again remove the height from line I L, at the point R,8.
The height from the 1:2 line is to cut off the 9 point.
at point Q, & brought from line 1:2. Ë cut off point 7. Then pull lines 4: 5.5: 6, 6:4. &
the others, number by number, are a little bit more in proective body, as you can see in the ointment.
Of course.
c A P. X v 1 I
The floorplan of the goddamn body in the body. The point of the competition B; the line of the plane S ∫ D E, the paralell line at the CB. The trajectory is two lines with right angles CE, the height
∫S∫ see F, & the perpendicular line to get the mi?ure DB. Format the plant in the heart, 8 pull "lines, two first, what are you going to do?
the height of the angles perpendicular to the body; & as in the height of the body.
Let's be careful in the plant V from YZ, and let's start from the beginning as you see the M N line:
& then pull two lines at right angles with and a touching line at points M N, M, ending with Q, &
the Ncon R: then the metamorphosis is removed from the V-plan Mezaria V, to the X-plan and brought from the Mad I point,
The plant VG,8 brought to me by M,P,N,O:
before you leave the same plant VZ, the flow rate is the same as M Q&N R: then pull the lines IL, PO, & Q B. Then take off the Y X line, and bring it from point L, cut the Q line that is in S, and similarly from point I, cut the QR line in T, which cosÏ is retracted.
perpendicularly to the height of the corners, & body, & RTSQ; & to better verify the height of the corners, & ba'e d'e?
So, what did you do, the price is to take me to the side of the pentagon of the body, carried by the point.
P, &O, ‡ cut the QR line, which will end at the S & T points, which cosÏ will see.
Checked the first height measurement, 8 ba and body angles: what heights will they reach?
Take the line of the plane, as you see in points E, H, AB, 8 E, denoted by the height of the RTSQ retracted angles, and then compete from points EH.AB & AE with many lines to point F, how many points. Then, parallel lines to the line of the plane, which touch every point of the plane.
Corner of the plant in the corner, 8 chimney chimney in front of the cut of the lines tending to F, as they see it.
Form dots, contrasting and lines with running numbers, 8 in the plan & profile,
as they see in the previous figure. Denoting the angle in the plant, the angle of the thread is indicated by the number 8 cosÏ of the other threads as well; it will still be in the same way.
Then take the canvas and put the body into the pro body, forming a work of art.
two lines at right angles to them, as they see them. AC AC & R. By accepting that all the angles
of the Aini plant, which can be found on the DB line, will have to be finished again on the DB line.
A: so that you don't have to take a plant of any kind, but you'll have to take the height from the profile. And in order to give principle to the height from the CE line, at the 2nd of November.
rophilo, & carried by the line. AC.AC ‡ cut the line R, in 2 that ?arrouted the line of e? or ango
The new line of the A plant has been removed from the BD line; from the BD line, the angles 1. or 3, which are equally many on both sides of the line, and carried by the R line, the line on both sides of the line in the points.
i & 3, & before the height in the profile from line C E to the point 1.3. & carried by the AC/AC line ‡ to cut the two angles: & similarly before the height in the profile from line C E to the point 1.3. & carried by the AC/AC line ‡ to cut the two angles: & similarly before the height in the profile from line AC/AC to the point 1.3. & 3.
the other one is from the B line D, the 4 and S angles equally from the line of many, and carried by the line
fR, 4.8 5. & pre the height from the CE line, to the 4.5. point of the profile, 8 flow rate,
from the line. AC A2, ‡ cut them 4 & 5, which cosÏ will find the other two corners, which then made the lines 1:2:2:3. 3:4.4:s & 5: "to get a bit of body in pro breast: cosÏ and I'll make the same order in the middle of the whole body, as you see.
c A r. xvIII
The A- body plant, a little bit in the background with the previous rule. The Point of the competition " -S i B: the line of the plane DE : the line at the point of the competition touching the point of the competition CB:
is∫ the right angle line at right angles with the lines CE: the height of the eye the point F: the line
perpendicular, to take the plant's miracles in BD. , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , . - ∫ inotto H
NOP. Then they pull for each point, many lines at right angles with the HP line. Then you have to go through the plant from the RadM, & range and lines, as you see in PQ:
When X Q is done, it paralyzes the NP line. Then take the ERA on the side of the triangle of that plant, brought to the O point, cut the PC line, which is inT: it is also the same as the ERA.
- - - - - 4 ∫ - l. - or in point Y cut the PG line, which is in Viche cosÏ will find the height of the body, as you see in the PVTQ points: to better certify this, you can cut the PG line in the plant RI, and bring it in the NX points, "PO line, which is in the NX points.
You'll see how much you can see in the VT points: the heights that can be carried on the plane line, as you can see in the VT points.
From the ESZ.AB points, then competing lines for all and the points in F: Still forming a lot of points.
paralell lines with the line of the plane, how many angles of the plan of the body can be seen as they are formed of dots, which will be contracted by numbers, as you see them.
They are then formed two lines at right angles of them, depending on which one of them is the king and the body in a comb, the vna of which is seen by the other AD. Then be removed from the EC line at point 1.8 carried by the AE AE line, and cut the AD line at point 1.8 carried by the AE AE line.
1. When you take my hand off the BD line, the angles are 2. & 3. which are equally as many from the line, 8.
carried by the AD line, ‡ to make the height from the CE line to the point 2: 3; & carried by the AE AE line, ‡ to cut the points 2.8 3. & then pull the lines 1:2. 2 3 8 3.1. that cosÏ ‡ to wine triangle of e? o Body in ri : Ilche ?eguir‡ in the remaining e? o Cor
Then, continuing with the same rule, 8 numbers against each other.
C A P, X I X.

5 Ia the plant of the spherical body A, a little bit in the heart with the previous rules, in particular
Decide; the competition point B, the plane line E D: the paralell line touching the competition point E D: the paralell line touching the plane point E D: the paralell line touching the plane point E D: the paralell line touching the plane point E D: the paralell line touching the plane point E D: the paralell line touching the plane point E D: the paralell line touching the plane point E D: the paralell line touching the plane point E D: the paralell line touching the plane point
238 concurrence CB: The Trauer line at right angles, with e lines E C: The point of Height F.
First look for the height of the body, forming it on the floor plan, as seen in the G compartment.
how is the A: in the first line, Tirin's lines IL:MN & OP; after taking off the HG line, the ES line of the ES plane, & S X is the new line from the G point to the M H line? or the plane line, on both sides of point S, is to be done at points R, & T; the middle line is to be taken off the other plane line from point G, to the line IL: & flow rate is to be done at points R, & T; the middle line is to be taken off the other plane line from point G, to the line IL: & flow rate is to be done at points R, & T; the middle line is to be taken off the other plane line from point G, to the line IL: & flow rate is to be taken off the plane line from point S, & T.
both parts of the point Yes ‡ to be done in the Q & V points: Then have many lines compete for the punch
to F, how many of the found corners of the body height, i.e. EQR STVX: & pull the lines, which see them formed of points, which are paralell with the plane line, 8 which are paralell with the plane line.
from every corner of the plant to every corner. - They then make two lines to the front of them, then put the AB, AB, & YZ lines in front of them, then put the AB, AB, & YZ lines in front of them, then put the AB, AB, & YZ lines in front of them, then put the AB, AB, & YZ lines in front of them, then put the AB, AB, & YZ lines in front of them, then put the AB, AB, & YZ lines in front of them, then put the AB, AB, & YZ lines in front of them, then put the AB, AB, & YZ lines in front of them, then put the AB, AB, & YZ lines in front of them.
born the couple wanting to start is to put the body in pro breast; Since the numbers, which are halfway up the body from the SF line at gi˘, still erupt for the other half from the SF line, ins˘, and brought by the line. AB-AB, cut the Y line 2" 1 from the Y line.
BD line, at the corners 3 & 13, which are equally many, 8 carried by the line.
ZY, do it at point 3, & 13 & then remove the height from the CE line at point 3.
13, & brought from the AB line, AB, is to cut and the points 3 & 13, then remove the height from the CE line at point 3.
said line B D, at the angles 4.8, 2.8 carried by the ZY line, in points 4.8 and 12.
then removed the height from the CE line, at point 4.8 12. & brought from the line. AB AB, ‡ cut there
said numbers 4.8 12. & equally before my arrival from the BD line, at the corners of the 8 and 1.
which are also many from and to the line; and carried by the ZY line, you have to do the same in the points
5.& 1 1,8 removed the height from the EC line, at the point 5.11.8 brought from the line. AB.AB,Ë size
The so-called numbers 5:& I 1. which, continuing with the rule, & numbers, will put them all
The angles of the body in the body in the pro-breast: still pull the lines from angle to angle, will lead to the whole body, as seen in the figure.